API Response to C# Model

Generate C# model classes directly from a real API JSON response.

How to Use API Response to C# Model

1
Enter InputFill in the fields above
2
ProcessClick the button to run the tool
3
Get ResultCopy your output instantly, no signup needed

API Response to C# Model — Free Developer Utility

API Response to C# Model turns a real, captured JSON response from any REST API directly into working C# model classes — the fastest way to build a typed client for a third-party API without manually reading documentation and guessing at property types. Copy the raw JSON response from your browser's network tab, Postman, or an API testing tool, paste it here, and get back a complete class hierarchy including any nested objects and arrays, with each array of objects becoming its own strongly-typed List property. This is particularly useful when integrating with APIs that have incomplete or outdated documentation — working from an actual response guarantees your model matches what the API really returns, catching optional fields or nested structures that docs sometimes miss.

Keywords and Search Terms

Developers searching for this tool use terms like: api response to c# model, api json to class, generate dto from api response, rest api model generator, api client model. Tooliby provides this utility free with no signup, no watermarks, and no data logging.

Privacy — Your Data is Never Stored

Every input you paste into Tooliby developer tools is processed in memory and immediately discarded. We do not log inputs, store results, or analyze your data.

Frequently Asked Questions

The actual response is often more reliable — API documentation can be outdated or incomplete, while a real response shows exactly what fields and nesting the API currently returns.
This tool generates a model from one sample response. If fields vary (optional fields sometimes missing), test with multiple sample responses and merge the resulting models manually.
Yes — as long as the response is valid JSON, the structure (REST envelope or GraphQL data wrapper) doesn't matter to the class generation logic.
The generated root class will include the envelope structure (e.g. a 'data' or 'result' wrapper property) exactly as it appears in your pasted JSON — this usually matches how you'd deserialize it anyway.
–
(0)
Rate:
Comments

No comments yet

Be the first to share your experience with this tool!